x^2-4=3 eching

$$x ^ { 2 } - 4 = 3$$

x uchun yechish

$$x=\sqrt{7}\approx 2,645751311$$

$$x=-\sqrt{7}\approx -2,645751311$$

Kvadrat ildizini topish bo'yicha qadamlar

4 ni ikki tarafga qo’shing.

$$x^{2}=3+4$$

7 olish uchun 3 va 4'ni qo'shing.

$$x^{2}=7$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{7} x=-\sqrt{7}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 3 ni ayirish.

$$x^{2}-4-3=0$$

-7 olish uchun -4 dan 3 ni ayirish.

$$x^{2}-7=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -7 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-7\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-7\right)}}{2}$$

-4 ni -7 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{28}}{2}$$

28 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{7}}{2}$$

x=\frac{0±2\sqrt{7}}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{7}$$

x=\frac{0±2\sqrt{7}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{7}$$

Tenglama yechildi.

$$x=\sqrt{7} x=-\sqrt{7}$$