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a+b=-32 ab=1\left(-2448\right)=-2448
Ifodani guruhlash orqali faktorlang. Avvalo, ifoda x^{2}+ax+bx-2448 sifatida qayta yozilishi kerak. a va b ni topish uchun yechiladigan tizimni sozlang.
1,-2448 2,-1224 3,-816 4,-612 6,-408 8,-306 9,-272 12,-204 16,-153 17,-144 18,-136 24,-102 34,-72 36,-68 48,-51
ab manfiy boʻlganda, a va b da qarama-qarshi belgilar bor. a+b manfiy boʻlganda, manfiy sonda musbatga nisbatdan kattaroq mutlaq qiymat bor. -2448-mahsulotni beruvchi bunday butun juftliklarni roʻyxat qiling.
1-2448=-2447 2-1224=-1222 3-816=-813 4-612=-608 6-408=-402 8-306=-298 9-272=-263 12-204=-192 16-153=-137 17-144=-127 18-136=-118 24-102=-78 34-72=-38 36-68=-32 48-51=-3
Har bir juftlik yigʻindisini hisoblang.
a=-68 b=36
Yechim – -32 yigʻindisini beruvchi juftlik.
\left(x^{2}-68x\right)+\left(36x-2448\right)
x^{2}-32x-2448 ni \left(x^{2}-68x\right)+\left(36x-2448\right) sifatida qaytadan yozish.
x\left(x-68\right)+36\left(x-68\right)
Birinchi guruhda x ni va ikkinchi guruhda 36 ni faktordan chiqaring.
\left(x-68\right)\left(x+36\right)
Distributiv funktsiyasidan foydalangan holda x-68 umumiy terminini chiqaring.
x^{2}-32x-2448=0
Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.
x=\frac{-\left(-32\right)±\sqrt{\left(-32\right)^{2}-4\left(-2448\right)}}{2}
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
x=\frac{-\left(-32\right)±\sqrt{1024-4\left(-2448\right)}}{2}
-32 kvadratini chiqarish.
x=\frac{-\left(-32\right)±\sqrt{1024+9792}}{2}
-4 ni -2448 marotabaga ko'paytirish.
x=\frac{-\left(-32\right)±\sqrt{10816}}{2}
1024 ni 9792 ga qo'shish.
x=\frac{-\left(-32\right)±104}{2}
10816 ning kvadrat ildizini chiqarish.
x=\frac{32±104}{2}
-32 ning teskarisi 32 ga teng.
x=\frac{136}{2}
x=\frac{32±104}{2} tenglamasini yeching, bunda ± musbat. 32 ni 104 ga qo'shish.
x=68
136 ni 2 ga bo'lish.
x=-\frac{72}{2}
x=\frac{32±104}{2} tenglamasini yeching, bunda ± manfiy. 32 dan 104 ni ayirish.
x=-36
-72 ni 2 ga bo'lish.
x^{2}-32x-2448=\left(x-68\right)\left(x-\left(-36\right)\right)
ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 68 ga va x_{2} uchun -36 ga bo‘ling.
x^{2}-32x-2448=\left(x-68\right)\left(x+36\right)
p-\left(-q\right) shaklining barcha amallarigani p+q ga soddalashtiring.