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x^{2}-3x-3=0
Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.
x=\frac{-\left(-3\right)±\sqrt{\left(-3\right)^{2}-4\left(-3\right)}}{2}
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
x=\frac{-\left(-3\right)±\sqrt{9-4\left(-3\right)}}{2}
-3 kvadratini chiqarish.
x=\frac{-\left(-3\right)±\sqrt{9+12}}{2}
-4 ni -3 marotabaga ko'paytirish.
x=\frac{-\left(-3\right)±\sqrt{21}}{2}
9 ni 12 ga qo'shish.
x=\frac{3±\sqrt{21}}{2}
-3 ning teskarisi 3 ga teng.
x=\frac{\sqrt{21}+3}{2}
x=\frac{3±\sqrt{21}}{2} tenglamasini yeching, bunda ± musbat. 3 ni \sqrt{21} ga qo'shish.
x=\frac{3-\sqrt{21}}{2}
x=\frac{3±\sqrt{21}}{2} tenglamasini yeching, bunda ± manfiy. 3 dan \sqrt{21} ni ayirish.
x^{2}-3x-3=\left(x-\frac{\sqrt{21}+3}{2}\right)\left(x-\frac{3-\sqrt{21}}{2}\right)
ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{3+\sqrt{21}}{2} ga va x_{2} uchun \frac{3-\sqrt{21}}{2} ga bo‘ling.