x^2-2x^2+6=2 eching

$$x ^ { 2 } - 2 x ^ { 2 } + 6 = 2$$

x uchun yechish

$$x=2$$

$$x=-2$$

Kvadrat ildizini topish bo'yicha qadamlar

-x^{2} ni olish uchun x^{2} va -2x^{2} ni birlashtirish.

$$-x^{2}+6=2$$

Ikkala tarafdan 6 ni ayirish.

$$-x^{2}=2-6$$

-4 olish uchun 2 dan 6 ni ayirish.

$$-x^{2}=-4$$

Ikki tarafini -1 ga bo‘ling.

$$x^{2}=\frac{-4}{-1}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-4}{-1} kasrini 4 ga soddalashtirish mumkin.

$$x^{2}=4$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=2 x=-2$$

Kvadrat tenglamalaridan foydalanish qoidalari

-x^{2} ni olish uchun x^{2} va -2x^{2} ni birlashtirish.

$$-x^{2}+6=2$$

Ikkala tarafdan 2 ni ayirish.

$$-x^{2}+6-2=0$$

4 olish uchun 6 dan 2 ni ayirish.

$$-x^{2}+4=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} -1 ni a, 0 ni b va 4 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-1\right)\times 4}}{2\left(-1\right)}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-1\right)\times 4}}{2\left(-1\right)}$$

-4 ni -1 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{4\times 4}}{2\left(-1\right)}$$

4 ni 4 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{16}}{2\left(-1\right)}$$

16 ning kvadrat ildizini chiqarish.

$$x=\frac{0±4}{2\left(-1\right)}$$

2 ni -1 marotabaga ko'paytirish.

$$x=\frac{0±4}{-2}$$

x=\frac{0±4}{-2} tenglamasini yeching, bunda ± musbat. 4 ni -2 ga bo'lish.

$$x=-2$$

x=\frac{0±4}{-2} tenglamasini yeching, bunda ± manfiy. -4 ni -2 ga bo'lish.

$$x=2$$

Tenglama yechildi.

$$x=-2 x=2$$