x^2-2x+17=0 eching

$$x ^ { 2 } - 2 x + 17 = 0$$

x uchun yechish (complex solution)

$$x=1+4i$$

$$x=1-4i$$

Kvadrat tenglamalaridan foydalanish qoidalari

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x^{2}-2x+17=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, -2 ni b va 17 ni c bilan almashtiring.

$$x=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}-4\times 17}}{2}$$

-2 kvadratini chiqarish.

$$x=\frac{-\left(-2\right)±\sqrt{4-4\times 17}}{2}$$

-4 ni 17 marotabaga ko'paytirish.

$$x=\frac{-\left(-2\right)±\sqrt{4-68}}{2}$$

4 ni -68 ga qo'shish.

$$x=\frac{-\left(-2\right)±\sqrt{-64}}{2}$$

-64 ning kvadrat ildizini chiqarish.

$$x=\frac{-\left(-2\right)±8i}{2}$$

-2 ning teskarisi 2 ga teng.

$$x=\frac{2±8i}{2}$$

x=\frac{2±8i}{2} tenglamasini yeching, bunda ± musbat. 2 ni 8i ga qo'shish.

$$x=\frac{2+8i}{2}$$

2+8i ni 2 ga bo'lish.

$$x=1+4i$$

x=\frac{2±8i}{2} tenglamasini yeching, bunda ± manfiy. 2 dan 8i ni ayirish.

$$x=\frac{2-8i}{2}$$

2-8i ni 2 ga bo'lish.

$$x=1-4i$$

Tenglama yechildi.

$$x=1+4i x=1-4i$$

Kvadratni yakunlash bo'yicha qadamlar

Bu kabi kvadrat tenglamalarni kvadratni yakunlab yechish mumkin. Kvadratni yechish uchun tenglama avval ushbu shaklda bo'lishi shart: x^{2}+bx=c.

$$x^{2}-2x+17=0$$

Tenglamaning ikkala tarafidan 17 ni ayirish.

$$x^{2}-2x+17-17=-17$$

O‘zidan 17 ayirilsa 0 qoladi.

$$x^{2}-2x=-17$$

-2 ni bo‘lish, x shartining koeffitsienti, 2 ga -1 olish uchun. Keyin, -1 ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.

$$x^{2}-2x+1=-17+1$$

-17 ni 1 ga qo'shish.

$$x^{2}-2x+1=-16$$

x^{2}-2x+1 omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.

$$\left(x-1\right)^{2}=-16$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$\sqrt{\left(x-1\right)^{2}}=\sqrt{-16}$$

Qisqartirish.

$$x-1=4i x-1=-4i$$

1 ni tenglamaning ikkala tarafiga qo'shish.

$$x=1+4i x=1-4i$$