x^2-18+1=0 eching

$$x ^ { 2 } - 18 + 1 = 0$$

x uchun yechish

$$x=\sqrt{17}\approx 4,123105626$$

$$x=-\sqrt{17}\approx -4,123105626$$

Kvadrat ildizini topish bo'yicha qadamlar

-17 olish uchun -18 va 1'ni qo'shing.

$$x^{2}-17=0$$

17 ni ikki tarafga qo’shing. Har qanday songa nolni qo‘shsangiz, o‘zi chiqadi.

$$x^{2}=17$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{17} x=-\sqrt{17}$$

Kvadrat tenglamalaridan foydalanish qoidalari

-17 olish uchun -18 va 1'ni qo'shing.

$$x^{2}-17=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -17 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-17\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-17\right)}}{2}$$

-4 ni -17 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{68}}{2}$$

68 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{17}}{2}$$

x=\frac{0±2\sqrt{17}}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{17}$$

x=\frac{0±2\sqrt{17}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{17}$$

Tenglama yechildi.

$$x=\sqrt{17} x=-\sqrt{17}$$