x^2-16x+26 eching

$$x ^ { 2 } - 16 x + 26$$

Omil

$$\left(x-\left(8-\sqrt{38}\right)\right)\left(x-\left(\sqrt{38}+8\right)\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$x^{2}-16x+26=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-\left(-16\right)±\sqrt{\left(-16\right)^{2}-4\times 26}}{2}$$

-16 kvadratini chiqarish.

$$x=\frac{-\left(-16\right)±\sqrt{256-4\times 26}}{2}$$

-4 ni 26 marotabaga ko'paytirish.

$$x=\frac{-\left(-16\right)±\sqrt{256-104}}{2}$$

256 ni -104 ga qo'shish.

$$x=\frac{-\left(-16\right)±\sqrt{152}}{2}$$

152 ning kvadrat ildizini chiqarish.

$$x=\frac{-\left(-16\right)±2\sqrt{38}}{2}$$

-16 ning teskarisi 16 ga teng.

$$x=\frac{16±2\sqrt{38}}{2}$$

x=\frac{16±2\sqrt{38}}{2} tenglamasini yeching, bunda ± musbat. 16 ni 2\sqrt{38} ga qo'shish.

$$x=\frac{2\sqrt{38}+16}{2}$$

16+2\sqrt{38} ni 2 ga bo'lish.

$$x=\sqrt{38}+8$$

x=\frac{16±2\sqrt{38}}{2} tenglamasini yeching, bunda ± manfiy. 16 dan 2\sqrt{38} ni ayirish.

$$x=\frac{16-2\sqrt{38}}{2}$$

16-2\sqrt{38} ni 2 ga bo'lish.

$$x=8-\sqrt{38}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 8+\sqrt{38} ga va x_{2} uchun 8-\sqrt{38} ga bo‘ling.

$$x^{2}-16x+26=\left(x-\left(\sqrt{38}+8\right)\right)\left(x-\left(8-\sqrt{38}\right)\right)$$

Baholash

$$x^{2}-16x+26$$