x^2-12=0 eching

$$x ^ { 2 } - 12 = 0$$

x uchun yechish

$$x=2\sqrt{3}\approx 3,464101615$$

$$x=-2\sqrt{3}\approx -3,464101615$$

Kvadrat ildizini topish bo'yicha qadamlar

12 ni ikki tarafga qo’shing. Har qanday songa nolni qo‘shsangiz, o‘zi chiqadi.

$$x^{2}=12$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=2\sqrt{3} x=-2\sqrt{3}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.

$$x^{2}-12=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -12 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-12\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-12\right)}}{2}$$

-4 ni -12 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{48}}{2}$$

48 ning kvadrat ildizini chiqarish.

$$x=\frac{0±4\sqrt{3}}{2}$$

x=\frac{0±4\sqrt{3}}{2} tenglamasini yeching, bunda ± musbat.

$$x=2\sqrt{3}$$

x=\frac{0±4\sqrt{3}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-2\sqrt{3}$$

Tenglama yechildi.

$$x=2\sqrt{3} x=-2\sqrt{3}$$