x^2-(-5)=+15 eching

$$x ^ { 2 } - ( - 5 ) = + 15$$

x uchun yechish

$$x=\sqrt{10}\approx 3,16227766$$

$$x=-\sqrt{10}\approx -3,16227766$$

Kvadrat ildizini topish bo'yicha qadamlar

-5 ning teskarisi 5 ga teng.

$$x^{2}+5=15$$

Ikkala tarafdan 5 ni ayirish.

$$x^{2}=15-5$$

10 olish uchun 15 dan 5 ni ayirish.

$$x^{2}=10$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{10} x=-\sqrt{10}$$

Kvadrat tenglamalaridan foydalanish qoidalari

-5 ning teskarisi 5 ga teng.

$$x^{2}+5=15$$

Ikkala tarafdan 15 ni ayirish.

$$x^{2}+5-15=0$$

-10 olish uchun 5 dan 15 ni ayirish.

$$x^{2}-10=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -10 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-10\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-10\right)}}{2}$$

-4 ni -10 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{40}}{2}$$

40 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{10}}{2}$$

x=\frac{0±2\sqrt{10}}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{10}$$

x=\frac{0±2\sqrt{10}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{10}$$

Tenglama yechildi.

$$x=\sqrt{10} x=-\sqrt{10}$$