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x^{2}\geq 46005119909369701466112
21 daraja ko‘rsatkichini 12 ga hisoblang va 46005119909369701466112 ni qiymatni oling.
x^{2}\geq \left(123834728448\sqrt{3}\right)^{2}
46005119909369701466112 ning kvadrat ildizini hisoblab, 123834728448\sqrt{3} natijaga ega bo‘ling. 46005119909369701466112 ni \left(123834728448\sqrt{3}\right)^{2} sifatida qaytadan yozish.
|x|\geq 123834728448\sqrt{3}
Tengsizlikda |x|\geq 123834728448\sqrt{3} bor.
x\leq -123834728448\sqrt{3}\text{; }x\geq 123834728448\sqrt{3}
|x|\geq 123834728448\sqrt{3} ni x\leq -123834728448\sqrt{3}\text{; }x\geq 123834728448\sqrt{3} sifatida qaytadan yozish.