x^2=2py eching

$$x ^ { 2 } = 2 p y$$

p uchun yechish (complex solution)

$$\left\{\begin{matrix}p=\frac{x^{2}}{2y}\text{, }&y\neq 0\\p\in \mathrm{C}\text{, }&x=0\text{ and }y=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$2py=x^{2}$$

Tenglama standart shaklda.

$$2yp=x^{2}$$

Ikki tarafini 2y ga bo‘ling.

$$\frac{2yp}{2y}=\frac{x^{2}}{2y}$$

2y ga bo'lish 2y ga ko'paytirishni bekor qiladi.

$$p=\frac{x^{2}}{2y}$$

p uchun yechish

$$\left\{\begin{matrix}p=\frac{x^{2}}{2y}\text{, }&y\neq 0\\p\in \mathrm{R}\text{, }&x=0\text{ and }y=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$2py=x^{2}$$

Tenglama standart shaklda.

$$2yp=x^{2}$$

Ikki tarafini 2y ga bo‘ling.

$$\frac{2yp}{2y}=\frac{x^{2}}{2y}$$

2y ga bo'lish 2y ga ko'paytirishni bekor qiladi.

$$p=\frac{x^{2}}{2y}$$

x uchun yechish (complex solution)

$$x=-\sqrt{y}\sqrt{2p}$$

$$x=\sqrt{y}\sqrt{2p}$$

x uchun yechish

$$x=\sqrt{2py}$$

$$x=-\sqrt{2py}\text{, }\left(y\geq 0\text{ and }p\geq 0\right)\text{ or }\left(p\leq 0\text{ and }y\leq 0\right)$$