x^2=16^2+17^2 eching

$$x ^ { 2 } = 16 ^ { 2 } + 17 ^ { 2 }$$

x uchun yechish

$$x=\sqrt{545}\approx 23,34523506$$

$$x=-\sqrt{545}\approx -23,34523506$$

Kvadrat ildizini topish bo'yicha qadamlar

2 daraja ko‘rsatkichini 16 ga hisoblang va 256 ni qiymatni oling.

$$x^{2}=256+17^{2}$$

2 daraja ko‘rsatkichini 17 ga hisoblang va 289 ni qiymatni oling.

$$x^{2}=256+289$$

545 olish uchun 256 va 289'ni qo'shing.

$$x^{2}=545$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{545} x=-\sqrt{545}$$

Kvadrat tenglamalaridan foydalanish qoidalari

2 daraja ko‘rsatkichini 16 ga hisoblang va 256 ni qiymatni oling.

$$x^{2}=256+17^{2}$$

2 daraja ko‘rsatkichini 17 ga hisoblang va 289 ni qiymatni oling.

$$x^{2}=256+289$$

545 olish uchun 256 va 289'ni qo'shing.

$$x^{2}=545$$

Ikkala tarafdan 545 ni ayirish.

$$x^{2}-545=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -545 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-545\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-545\right)}}{2}$$

-4 ni -545 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{2180}}{2}$$

2180 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{545}}{2}$$

x=\frac{0±2\sqrt{545}}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{545}$$

x=\frac{0±2\sqrt{545}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{545}$$

Tenglama yechildi.

$$x=\sqrt{545} x=-\sqrt{545}$$