x^2=12^2-6^2 eching

$$x ^ { 2 } = 12 ^ { 2 } - 6 ^ { 2 }$$

x uchun yechish

$$x=6\sqrt{3}\approx 10,392304845$$

$$x=-6\sqrt{3}\approx -10,392304845$$

Kvadrat ildizini topish bo'yicha qadamlar

2 daraja ko‘rsatkichini 12 ga hisoblang va 144 ni qiymatni oling.

$$x^{2}=144-6^{2}$$

2 daraja ko‘rsatkichini 6 ga hisoblang va 36 ni qiymatni oling.

$$x^{2}=144-36$$

108 olish uchun 144 dan 36 ni ayirish.

$$x^{2}=108$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=6\sqrt{3} x=-6\sqrt{3}$$

Kvadrat tenglamalaridan foydalanish qoidalari

2 daraja ko‘rsatkichini 12 ga hisoblang va 144 ni qiymatni oling.

$$x^{2}=144-6^{2}$$

2 daraja ko‘rsatkichini 6 ga hisoblang va 36 ni qiymatni oling.

$$x^{2}=144-36$$

108 olish uchun 144 dan 36 ni ayirish.

$$x^{2}=108$$

Ikkala tarafdan 108 ni ayirish.

$$x^{2}-108=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -108 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-108\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-108\right)}}{2}$$

-4 ni -108 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{432}}{2}$$

432 ning kvadrat ildizini chiqarish.

$$x=\frac{0±12\sqrt{3}}{2}$$

x=\frac{0±12\sqrt{3}}{2} tenglamasini yeching, bunda ± musbat.

$$x=6\sqrt{3}$$

x=\frac{0±12\sqrt{3}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-6\sqrt{3}$$

Tenglama yechildi.

$$x=6\sqrt{3} x=-6\sqrt{3}$$