x^2=4a/sqrt{3} eching

$$x ^ { 2 } = \frac { 4 a } { \sqrt { 3 } }$$

a uchun yechish

$$a=\frac{\sqrt{3}x^{2}}{4}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\frac{4a}{\sqrt{3}} maxrajini \sqrt{3} orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.

$$x^{2}=\frac{4a\sqrt{3}}{\left(\sqrt{3}\right)^{2}}$$

\sqrt{3} kvadrati – 3.

$$x^{2}=\frac{4a\sqrt{3}}{3}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\frac{4a\sqrt{3}}{3}=x^{2}$$

Tenglamaning ikkala tarafini 3 ga ko'paytirish.

$$4a\sqrt{3}=3x^{2}$$

Tenglama standart shaklda.

$$4\sqrt{3}a=3x^{2}$$

Ikki tarafini 4\sqrt{3} ga bo‘ling.

$$\frac{4\sqrt{3}a}{4\sqrt{3}}=\frac{3x^{2}}{4\sqrt{3}}$$

4\sqrt{3} ga bo'lish 4\sqrt{3} ga ko'paytirishni bekor qiladi.

$$a=\frac{3x^{2}}{4\sqrt{3}}$$

3x^{2} ni 4\sqrt{3} ga bo'lish.

$$a=\frac{\sqrt{3}x^{2}}{4}$$

x uchun yechish (complex solution)

$$x=-\frac{2\times 3^{\frac{3}{4}}\sqrt{a}}{3}$$

$$x=\frac{2\times 3^{\frac{3}{4}}\sqrt{a}}{3}$$

x uchun yechish

$$x=\frac{2\times 3^{\frac{3}{4}}\sqrt{a}}{3}$$

$$x=-\frac{2\times 3^{\frac{3}{4}}\sqrt{a}}{3}\text{, }a\geq 0$$