x^2+x^2x^12 eching

$$x ^ { 2 } + x ^ { 2 } x ^ { 12 }$$

Omil

$$x^{2}\left(x^{4}+1\right)\left(x^{8}-x^{4}+1\right)$$

Yechim qadamlari

x^{2} omili.

$$x^{2}\left(1+x^{12}\right)$$

Hisoblang: 1+x^{12}. 1+x^{12} ni \left(x^{4}\right)^{3}+1^{3} sifatida qaytadan yozish. Kublar yigʻindisini ushbu formula bilan hisoblash mumkin: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).

$$\left(x^{4}+1\right)\left(x^{8}-x^{4}+1\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing. Quyidagi koʻphadlar faktorlanmagan, ularda hech qanday ratsional ildizlar topilmadi: x^{8}-x^{4}+1,x^{4}+1.

$$x^{2}\left(x^{4}+1\right)\left(x^{8}-x^{4}+1\right)$$

Baholash

$$x^{14}+x^{2}$$

Yechim qadamlari

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. 2 va 12 ni qo‘shib, 14 ni oling.

$$x^{2}+x^{14}$$