x^2+x+12x-5 eching

$$x ^ { 2 } + x + 12 x - 5$$

Omil

$$\left(x-\frac{-3\sqrt{21}-13}{2}\right)\left(x-\frac{3\sqrt{21}-13}{2}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

13x ni olish uchun x va 12x ni birlashtirish.

$$factor(x^{2}+13x-5)$$

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$x^{2}+13x-5=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-13±\sqrt{13^{2}-4\left(-5\right)}}{2}$$

13 kvadratini chiqarish.

$$x=\frac{-13±\sqrt{169-4\left(-5\right)}}{2}$$

-4 ni -5 marotabaga ko'paytirish.

$$x=\frac{-13±\sqrt{169+20}}{2}$$

169 ni 20 ga qo'shish.

$$x=\frac{-13±\sqrt{189}}{2}$$

189 ning kvadrat ildizini chiqarish.

$$x=\frac{-13±3\sqrt{21}}{2}$$

x=\frac{-13±3\sqrt{21}}{2} tenglamasini yeching, bunda ± musbat. -13 ni 3\sqrt{21} ga qo'shish.

$$x=\frac{3\sqrt{21}-13}{2}$$

x=\frac{-13±3\sqrt{21}}{2} tenglamasini yeching, bunda ± manfiy. -13 dan 3\sqrt{21} ni ayirish.

$$x=\frac{-3\sqrt{21}-13}{2}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-13+3\sqrt{21}}{2} ga va x_{2} uchun \frac{-13-3\sqrt{21}}{2} ga bo‘ling.

$$x^{2}+13x-5=\left(x-\frac{3\sqrt{21}-13}{2}\right)\left(x-\frac{-3\sqrt{21}-13}{2}\right)$$

Baholash

$$x^{2}+13x-5$$

Yechim qadamlari

13x ni olish uchun x va 12x ni birlashtirish.

$$x^{2}+13x-5$$