x^2+9x-20 eching

$$x ^ { 2 } + 9 x - 20$$

Omil

$$\left(x-\frac{-\sqrt{161}-9}{2}\right)\left(x-\frac{\sqrt{161}-9}{2}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$x^{2}+9x-20=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-9±\sqrt{9^{2}-4\left(-20\right)}}{2}$$

9 kvadratini chiqarish.

$$x=\frac{-9±\sqrt{81-4\left(-20\right)}}{2}$$

-4 ni -20 marotabaga ko'paytirish.

$$x=\frac{-9±\sqrt{81+80}}{2}$$

81 ni 80 ga qo'shish.

$$x=\frac{-9±\sqrt{161}}{2}$$

x=\frac{-9±\sqrt{161}}{2} tenglamasini yeching, bunda ± musbat. -9 ni \sqrt{161} ga qo'shish.

$$x=\frac{\sqrt{161}-9}{2}$$

x=\frac{-9±\sqrt{161}}{2} tenglamasini yeching, bunda ± manfiy. -9 dan \sqrt{161} ni ayirish.

$$x=\frac{-\sqrt{161}-9}{2}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-9+\sqrt{161}}{2} ga va x_{2} uchun \frac{-9-\sqrt{161}}{2} ga bo‘ling.

$$x^{2}+9x-20=\left(x-\frac{\sqrt{161}-9}{2}\right)\left(x-\frac{-\sqrt{161}-9}{2}\right)$$

Baholash

$$x^{2}+9x-20$$