x^2+9x+4x+6 eching

$$x ^ { 2 } + 9 x + 4 x + 6$$

Omil

$$\left(x-\frac{-\sqrt{145}-13}{2}\right)\left(x-\frac{\sqrt{145}-13}{2}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

13x ni olish uchun 9x va 4x ni birlashtirish.

$$factor(x^{2}+13x+6)$$

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$x^{2}+13x+6=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-13±\sqrt{13^{2}-4\times 6}}{2}$$

13 kvadratini chiqarish.

$$x=\frac{-13±\sqrt{169-4\times 6}}{2}$$

-4 ni 6 marotabaga ko'paytirish.

$$x=\frac{-13±\sqrt{169-24}}{2}$$

169 ni -24 ga qo'shish.

$$x=\frac{-13±\sqrt{145}}{2}$$

x=\frac{-13±\sqrt{145}}{2} tenglamasini yeching, bunda ± musbat. -13 ni \sqrt{145} ga qo'shish.

$$x=\frac{\sqrt{145}-13}{2}$$

x=\frac{-13±\sqrt{145}}{2} tenglamasini yeching, bunda ± manfiy. -13 dan \sqrt{145} ni ayirish.

$$x=\frac{-\sqrt{145}-13}{2}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-13+\sqrt{145}}{2} ga va x_{2} uchun \frac{-13-\sqrt{145}}{2} ga bo‘ling.

$$x^{2}+13x+6=\left(x-\frac{\sqrt{145}-13}{2}\right)\left(x-\frac{-\sqrt{145}-13}{2}\right)$$

Baholash

$$x^{2}+13x+6$$

Yechim qadamlari

13x ni olish uchun 9x va 4x ni birlashtirish.

$$x^{2}+13x+6$$