x^2+8x-576 eching

$$x ^ { 2 } + 8 x - 576$$

Omil

$$\left(x-\left(-4\sqrt{37}-4\right)\right)\left(x-\left(4\sqrt{37}-4\right)\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$x^{2}+8x-576=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-8±\sqrt{8^{2}-4\left(-576\right)}}{2}$$

8 kvadratini chiqarish.

$$x=\frac{-8±\sqrt{64-4\left(-576\right)}}{2}$$

-4 ni -576 marotabaga ko'paytirish.

$$x=\frac{-8±\sqrt{64+2304}}{2}$$

64 ni 2304 ga qo'shish.

$$x=\frac{-8±\sqrt{2368}}{2}$$

2368 ning kvadrat ildizini chiqarish.

$$x=\frac{-8±8\sqrt{37}}{2}$$

x=\frac{-8±8\sqrt{37}}{2} tenglamasini yeching, bunda ± musbat. -8 ni 8\sqrt{37} ga qo'shish.

$$x=\frac{8\sqrt{37}-8}{2}$$

-8+8\sqrt{37} ni 2 ga bo'lish.

$$x=4\sqrt{37}-4$$

x=\frac{-8±8\sqrt{37}}{2} tenglamasini yeching, bunda ± manfiy. -8 dan 8\sqrt{37} ni ayirish.

$$x=\frac{-8\sqrt{37}-8}{2}$$

-8-8\sqrt{37} ni 2 ga bo'lish.

$$x=-4\sqrt{37}-4$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun -4+4\sqrt{37} ga va x_{2} uchun -4-4\sqrt{37} ga bo‘ling.

$$x^{2}+8x-576=\left(x-\left(4\sqrt{37}-4\right)\right)\left(x-\left(-4\sqrt{37}-4\right)\right)$$

Baholash

$$x^{2}+8x-576$$