x^2+8x=4y-12 eching

$$x ^ { 2 } + 8 x = 4 y - 12$$

y uchun yechish

$$y=\frac{\left(x+2\right)\left(x+6\right)}{4}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$4y-12=x^{2}+8x$$

12 ni ikki tarafga qo’shing.

$$4y=x^{2}+8x+12$$

Ikki tarafini 4 ga bo‘ling.

$$\frac{4y}{4}=\frac{\left(x+2\right)\left(x+6\right)}{4}$$

4 ga bo'lish 4 ga ko'paytirishni bekor qiladi.

$$y=\frac{\left(x+2\right)\left(x+6\right)}{4}$$

x uchun yechish (complex solution)

$$x=2\sqrt{y+1}-4$$

$$x=-2\sqrt{y+1}-4$$

x uchun yechish

$$x=2\sqrt{y+1}-4$$

$$x=-2\sqrt{y+1}-4\text{, }y\geq -1$$