x^2+8^2=(x+4)^2 eching

$$x ^ { 2 } + 8 ^ { 2 } = ( x + 4 ) ^ { 2 }$$

x uchun yechish

$$x=6$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 daraja ko‘rsatkichini 8 ga hisoblang va 64 ni qiymatni oling.

$$x^{2}+64=\left(x+4\right)^{2}$$

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(x+4\right)^{2} kengaytirilishi uchun ishlating.

$$x^{2}+64=x^{2}+8x+16$$

Ikkala tarafdan x^{2} ni ayirish.

$$x^{2}+64-x^{2}=8x+16$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$64=8x+16$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$8x+16=64$$

Ikkala tarafdan 16 ni ayirish.

$$8x=64-16$$

48 olish uchun 64 dan 16 ni ayirish.

$$8x=48$$

Ikki tarafini 8 ga bo‘ling.

$$x=\frac{48}{8}$$

6 ni olish uchun 48 ni 8 ga bo‘ling.

$$x=6$$