x^2+7^2=2 eching

$$x ^ { 2 } + 7 ^ { 2 } = 2$$

x uchun yechish (complex solution)

$$x=-\sqrt{47}i\approx -0-6,8556546i$$

$$x=\sqrt{47}i\approx 6,8556546i$$

Kvadrat ildizini topish bo'yicha qadamlar

2 daraja ko‘rsatkichini 7 ga hisoblang va 49 ni qiymatni oling.

$$x^{2}+49=2$$

Ikkala tarafdan 49 ni ayirish.

$$x^{2}=2-49$$

-47 olish uchun 2 dan 49 ni ayirish.

$$x^{2}=-47$$

Tenglama yechildi.

$$x=\sqrt{47}i x=-\sqrt{47}i$$

Kvadrat tenglamalaridan foydalanish qoidalari

2 daraja ko‘rsatkichini 7 ga hisoblang va 49 ni qiymatni oling.

$$x^{2}+49=2$$

Ikkala tarafdan 2 ni ayirish.

$$x^{2}+49-2=0$$

47 olish uchun 49 dan 2 ni ayirish.

$$x^{2}+47=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va 47 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\times 47}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\times 47}}{2}$$

-4 ni 47 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-188}}{2}$$

-188 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{47}i}{2}$$

x=\frac{0±2\sqrt{47}i}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{47}i$$

x=\frac{0±2\sqrt{47}i}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{47}i$$

Tenglama yechildi.

$$x=\sqrt{47}i x=-\sqrt{47}i$$