x^2+7=10 eching

$$x ^ { 2 } + 7 = 10$$

x uchun yechish

$$x=\sqrt{3}\approx 1,732050808$$

$$x=-\sqrt{3}\approx -1,732050808$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 7 ni ayirish.

$$x^{2}=10-7$$

3 olish uchun 10 dan 7 ni ayirish.

$$x^{2}=3$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{3} x=-\sqrt{3}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 10 ni ayirish.

$$x^{2}+7-10=0$$

-3 olish uchun 7 dan 10 ni ayirish.

$$x^{2}-3=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -3 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-3\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-3\right)}}{2}$$

-4 ni -3 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{12}}{2}$$

12 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{3}}{2}$$

x=\frac{0±2\sqrt{3}}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{3}$$

x=\frac{0±2\sqrt{3}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{3}$$

Tenglama yechildi.

$$x=\sqrt{3} x=-\sqrt{3}$$