x^2+64x+8 eching

$$x ^ { 2 } + 64 x + 8$$

Omil

$$\left(x-\left(-2\sqrt{254}-32\right)\right)\left(x-\left(2\sqrt{254}-32\right)\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$x^{2}+64x+8=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-64±\sqrt{64^{2}-4\times 8}}{2}$$

64 kvadratini chiqarish.

$$x=\frac{-64±\sqrt{4096-4\times 8}}{2}$$

-4 ni 8 marotabaga ko'paytirish.

$$x=\frac{-64±\sqrt{4096-32}}{2}$$

4096 ni -32 ga qo'shish.

$$x=\frac{-64±\sqrt{4064}}{2}$$

4064 ning kvadrat ildizini chiqarish.

$$x=\frac{-64±4\sqrt{254}}{2}$$

x=\frac{-64±4\sqrt{254}}{2} tenglamasini yeching, bunda ± musbat. -64 ni 4\sqrt{254} ga qo'shish.

$$x=\frac{4\sqrt{254}-64}{2}$$

-64+4\sqrt{254} ni 2 ga bo'lish.

$$x=2\sqrt{254}-32$$

x=\frac{-64±4\sqrt{254}}{2} tenglamasini yeching, bunda ± manfiy. -64 dan 4\sqrt{254} ni ayirish.

$$x=\frac{-4\sqrt{254}-64}{2}$$

-64-4\sqrt{254} ni 2 ga bo'lish.

$$x=-2\sqrt{254}-32$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun -32+2\sqrt{254} ga va x_{2} uchun -32-2\sqrt{254} ga bo‘ling.

$$x^{2}+64x+8=\left(x-\left(2\sqrt{254}-32\right)\right)\left(x-\left(-2\sqrt{254}-32\right)\right)$$

Baholash

$$x^{2}+64x+8$$