x^2+6x-3= eching

$$x ^ { 2 } + 6 x - 3 =$$

Omil

$$\left(x-\left(-2\sqrt{3}-3\right)\right)\left(x-\left(2\sqrt{3}-3\right)\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$x^{2}+6x-3=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-6±\sqrt{6^{2}-4\left(-3\right)}}{2}$$

6 kvadratini chiqarish.

$$x=\frac{-6±\sqrt{36-4\left(-3\right)}}{2}$$

-4 ni -3 marotabaga ko'paytirish.

$$x=\frac{-6±\sqrt{36+12}}{2}$$

36 ni 12 ga qo'shish.

$$x=\frac{-6±\sqrt{48}}{2}$$

48 ning kvadrat ildizini chiqarish.

$$x=\frac{-6±4\sqrt{3}}{2}$$

x=\frac{-6±4\sqrt{3}}{2} tenglamasini yeching, bunda ± musbat. -6 ni 4\sqrt{3} ga qo'shish.

$$x=\frac{4\sqrt{3}-6}{2}$$

-6+4\sqrt{3} ni 2 ga bo'lish.

$$x=2\sqrt{3}-3$$

x=\frac{-6±4\sqrt{3}}{2} tenglamasini yeching, bunda ± manfiy. -6 dan 4\sqrt{3} ni ayirish.

$$x=\frac{-4\sqrt{3}-6}{2}$$

-6-4\sqrt{3} ni 2 ga bo'lish.

$$x=-2\sqrt{3}-3$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun -3+2\sqrt{3} ga va x_{2} uchun -3-2\sqrt{3} ga bo‘ling.

$$x^{2}+6x-3=\left(x-\left(2\sqrt{3}-3\right)\right)\left(x-\left(-2\sqrt{3}-3\right)\right)$$

Baholash

$$x^{2}+6x-3$$