x^2+6x=-6 eching

$$x ^ { 2 } + 6 x = - 6$$

x uchun yechish

$$x=\sqrt{3}-3\approx -1,267949192$$

$$x=-\sqrt{3}-3\approx -4,732050808$$

Kvadrat tenglamalaridan foydalanish qoidalari

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x^{2}+6x=-6$$

6 ni tenglamaning ikkala tarafiga qo'shish.

$$x^{2}+6x-\left(-6\right)=-6-\left(-6\right)$$

O‘zidan -6 ayirilsa 0 qoladi.

$$x^{2}+6x-\left(-6\right)=0$$

0 dan -6 ni ayirish.

$$x^{2}+6x+6=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 6 ni b va 6 ni c bilan almashtiring.

$$x=\frac{-6±\sqrt{6^{2}-4\times 6}}{2}$$

6 kvadratini chiqarish.

$$x=\frac{-6±\sqrt{36-4\times 6}}{2}$$

-4 ni 6 marotabaga ko'paytirish.

$$x=\frac{-6±\sqrt{36-24}}{2}$$

36 ni -24 ga qo'shish.

$$x=\frac{-6±\sqrt{12}}{2}$$

12 ning kvadrat ildizini chiqarish.

$$x=\frac{-6±2\sqrt{3}}{2}$$

x=\frac{-6±2\sqrt{3}}{2} tenglamasini yeching, bunda ± musbat. -6 ni 2\sqrt{3} ga qo'shish.

$$x=\frac{2\sqrt{3}-6}{2}$$

-6+2\sqrt{3} ni 2 ga bo'lish.

$$x=\sqrt{3}-3$$

x=\frac{-6±2\sqrt{3}}{2} tenglamasini yeching, bunda ± manfiy. -6 dan 2\sqrt{3} ni ayirish.

$$x=\frac{-2\sqrt{3}-6}{2}$$

-6-2\sqrt{3} ni 2 ga bo'lish.

$$x=-\sqrt{3}-3$$

Tenglama yechildi.

$$x=\sqrt{3}-3 x=-\sqrt{3}-3$$

Kvadratni yakunlash bo'yicha qadamlar

Bu kabi kvadrat tenglamalarni kvadratni yakunlab yechish mumkin. Kvadratni yechish uchun tenglama avval ushbu shaklda bo'lishi shart: x^{2}+bx=c.

$$x^{2}+6x=-6$$

6 ni bo‘lish, x shartining koeffitsienti, 2 ga 3 olish uchun. Keyin, 3 ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.

$$x^{2}+6x+3^{2}=-6+3^{2}$$

3 kvadratini chiqarish.

$$x^{2}+6x+9=-6+9$$

-6 ni 9 ga qo'shish.

$$x^{2}+6x+9=3$$

x^{2}+6x+9 omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.

$$\left(x+3\right)^{2}=3$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$\sqrt{\left(x+3\right)^{2}}=\sqrt{3}$$

Qisqartirish.

$$x+3=\sqrt{3} x+3=-\sqrt{3}$$

Tenglamaning ikkala tarafidan 3 ni ayirish.

$$x=\sqrt{3}-3 x=-\sqrt{3}-3$$