x^2+6^3=498 eching

$$x ^ { 2 } + 6 ^ { 3 } = 498$$

x uchun yechish

$$x=\sqrt{282}\approx 16,792855624$$

$$x=-\sqrt{282}\approx -16,792855624$$

Kvadrat ildizini topish bo'yicha qadamlar

3 daraja ko‘rsatkichini 6 ga hisoblang va 216 ni qiymatni oling.

$$x^{2}+216=498$$

Ikkala tarafdan 216 ni ayirish.

$$x^{2}=498-216$$

282 olish uchun 498 dan 216 ni ayirish.

$$x^{2}=282$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{282} x=-\sqrt{282}$$

Kvadrat tenglamalaridan foydalanish qoidalari

3 daraja ko‘rsatkichini 6 ga hisoblang va 216 ni qiymatni oling.

$$x^{2}+216=498$$

Ikkala tarafdan 498 ni ayirish.

$$x^{2}+216-498=0$$

-282 olish uchun 216 dan 498 ni ayirish.

$$x^{2}-282=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -282 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-282\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-282\right)}}{2}$$

-4 ni -282 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{1128}}{2}$$

1128 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{282}}{2}$$

x=\frac{0±2\sqrt{282}}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{282}$$

x=\frac{0±2\sqrt{282}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{282}$$

Tenglama yechildi.

$$x=\sqrt{282} x=-\sqrt{282}$$