x^2+6=32 eching

$$x ^ { 2 } + 6 = 32$$

x uchun yechish

$$x=\sqrt{26}\approx 5,099019514$$

$$x=-\sqrt{26}\approx -5,099019514$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 6 ni ayirish.

$$x^{2}=32-6$$

26 olish uchun 32 dan 6 ni ayirish.

$$x^{2}=26$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{26} x=-\sqrt{26}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 32 ni ayirish.

$$x^{2}+6-32=0$$

-26 olish uchun 6 dan 32 ni ayirish.

$$x^{2}-26=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -26 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-26\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-26\right)}}{2}$$

-4 ni -26 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{104}}{2}$$

104 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{26}}{2}$$

x=\frac{0±2\sqrt{26}}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{26}$$

x=\frac{0±2\sqrt{26}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{26}$$

Tenglama yechildi.

$$x=\sqrt{26} x=-\sqrt{26}$$