x^2+4x-8 eching

$$x ^ { 2 } + 4 x - 8$$

Omil

$$\left(x-\left(-2\sqrt{3}-2\right)\right)\left(x-\left(2\sqrt{3}-2\right)\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$x^{2}+4x-8=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-4±\sqrt{4^{2}-4\left(-8\right)}}{2}$$

4 kvadratini chiqarish.

$$x=\frac{-4±\sqrt{16-4\left(-8\right)}}{2}$$

-4 ni -8 marotabaga ko'paytirish.

$$x=\frac{-4±\sqrt{16+32}}{2}$$

16 ni 32 ga qo'shish.

$$x=\frac{-4±\sqrt{48}}{2}$$

48 ning kvadrat ildizini chiqarish.

$$x=\frac{-4±4\sqrt{3}}{2}$$

x=\frac{-4±4\sqrt{3}}{2} tenglamasini yeching, bunda ± musbat. -4 ni 4\sqrt{3} ga qo'shish.

$$x=\frac{4\sqrt{3}-4}{2}$$

-4+4\sqrt{3} ni 2 ga bo'lish.

$$x=2\sqrt{3}-2$$

x=\frac{-4±4\sqrt{3}}{2} tenglamasini yeching, bunda ± manfiy. -4 dan 4\sqrt{3} ni ayirish.

$$x=\frac{-4\sqrt{3}-4}{2}$$

-4-4\sqrt{3} ni 2 ga bo'lish.

$$x=-2\sqrt{3}-2$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun -2+2\sqrt{3} ga va x_{2} uchun -2-2\sqrt{3} ga bo‘ling.

$$x^{2}+4x-8=\left(x-\left(2\sqrt{3}-2\right)\right)\left(x-\left(-2\sqrt{3}-2\right)\right)$$

Baholash

$$x^{2}+4x-8$$