x^2+4=45 eching

$$x ^ { 2 } + 4 = 45$$

x uchun yechish

$$x=\sqrt{41}\approx 6,403124237$$

$$x=-\sqrt{41}\approx -6,403124237$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 4 ni ayirish.

$$x^{2}=45-4$$

41 olish uchun 45 dan 4 ni ayirish.

$$x^{2}=41$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{41} x=-\sqrt{41}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 45 ni ayirish.

$$x^{2}+4-45=0$$

-41 olish uchun 4 dan 45 ni ayirish.

$$x^{2}-41=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -41 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-41\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-41\right)}}{2}$$

-4 ni -41 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{164}}{2}$$

164 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{41}}{2}$$

x=\frac{0±2\sqrt{41}}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{41}$$

x=\frac{0±2\sqrt{41}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{41}$$

Tenglama yechildi.

$$x=\sqrt{41} x=-\sqrt{41}$$