x^2+32x+1 eching

$$x ^ { 2 } + 32 x + 1$$

Omil

$$\left(x-\left(-\sqrt{255}-16\right)\right)\left(x-\left(\sqrt{255}-16\right)\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$x^{2}+32x+1=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-32±\sqrt{32^{2}-4}}{2}$$

32 kvadratini chiqarish.

$$x=\frac{-32±\sqrt{1024-4}}{2}$$

1024 ni -4 ga qo'shish.

$$x=\frac{-32±\sqrt{1020}}{2}$$

1020 ning kvadrat ildizini chiqarish.

$$x=\frac{-32±2\sqrt{255}}{2}$$

x=\frac{-32±2\sqrt{255}}{2} tenglamasini yeching, bunda ± musbat. -32 ni 2\sqrt{255} ga qo'shish.

$$x=\frac{2\sqrt{255}-32}{2}$$

-32+2\sqrt{255} ni 2 ga bo'lish.

$$x=\sqrt{255}-16$$

x=\frac{-32±2\sqrt{255}}{2} tenglamasini yeching, bunda ± manfiy. -32 dan 2\sqrt{255} ni ayirish.

$$x=\frac{-2\sqrt{255}-32}{2}$$

-32-2\sqrt{255} ni 2 ga bo'lish.

$$x=-\sqrt{255}-16$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun -16+\sqrt{255} ga va x_{2} uchun -16-\sqrt{255} ga bo‘ling.

$$x^{2}+32x+1=\left(x-\left(\sqrt{255}-16\right)\right)\left(x-\left(-\sqrt{255}-16\right)\right)$$

Baholash

$$x^{2}+32x+1$$