x^2+3x+9=(x+2)^2-17 eching

$$x ^ { 2 } + 3 x + 9 = ( x + 2 ) ^ { 2 } - 17$$

x uchun yechish

$$x=22$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(x+2\right)^{2} kengaytirilishi uchun ishlating.

$$x^{2}+3x+9=x^{2}+4x+4-17$$

-13 olish uchun 4 dan 17 ni ayirish.

$$x^{2}+3x+9=x^{2}+4x-13$$

Ikkala tarafdan x^{2} ni ayirish.

$$x^{2}+3x+9-x^{2}=4x-13$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$3x+9=4x-13$$

Ikkala tarafdan 4x ni ayirish.

$$3x+9-4x=-13$$

-x ni olish uchun 3x va -4x ni birlashtirish.

$$-x+9=-13$$

Ikkala tarafdan 9 ni ayirish.

$$-x=-13-9$$

-22 olish uchun -13 dan 9 ni ayirish.

$$-x=-22$$

Ikkala tarafini -1 ga ko‘paytiring.

$$x=22$$