x^2+3x+8=(x+2)^2-19 eching

$$x ^ { 2 } + 3 x + 8 = ( x + 2 ) ^ { 2 } - 19$$

x uchun yechish

$$x=23$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(x+2\right)^{2} kengaytirilishi uchun ishlating.

$$x^{2}+3x+8=x^{2}+4x+4-19$$

-15 olish uchun 4 dan 19 ni ayirish.

$$x^{2}+3x+8=x^{2}+4x-15$$

Ikkala tarafdan x^{2} ni ayirish.

$$x^{2}+3x+8-x^{2}=4x-15$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$3x+8=4x-15$$

Ikkala tarafdan 4x ni ayirish.

$$3x+8-4x=-15$$

-x ni olish uchun 3x va -4x ni birlashtirish.

$$-x+8=-15$$

Ikkala tarafdan 8 ni ayirish.

$$-x=-15-8$$

-23 olish uchun -15 dan 8 ni ayirish.

$$-x=-23$$

Ikkala tarafini -1 ga ko‘paytiring.

$$x=23$$