x^2+25=0 eching

$$x ^ { 2 } + 25 = 0$$

x uchun yechish (complex solution)

$$x=-5i$$

$$x=5i$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 25 ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$x^{2}=-25$$

Tenglama yechildi.

$$x=5i x=-5i$$

Kvadrat tenglamalaridan foydalanish qoidalari

Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.

$$x^{2}+25=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va 25 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\times 25}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\times 25}}{2}$$

-4 ni 25 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-100}}{2}$$

-100 ning kvadrat ildizini chiqarish.

$$x=\frac{0±10i}{2}$$

x=\frac{0±10i}{2} tenglamasini yeching, bunda ± musbat.

$$x=5i$$

x=\frac{0±10i}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-5i$$

Tenglama yechildi.

$$x=5i x=-5i$$