x^2+2x+26=0 eching

$$x ^ { 2 } + 2 x + 26 = 0$$

x uchun yechish (complex solution)

$$x=-1+5i$$

$$x=-1-5i$$

Kvadrat tenglamalaridan foydalanish qoidalari

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x^{2}+2x+26=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 2 ni b va 26 ni c bilan almashtiring.

$$x=\frac{-2±\sqrt{2^{2}-4\times 26}}{2}$$

2 kvadratini chiqarish.

$$x=\frac{-2±\sqrt{4-4\times 26}}{2}$$

-4 ni 26 marotabaga ko'paytirish.

$$x=\frac{-2±\sqrt{4-104}}{2}$$

4 ni -104 ga qo'shish.

$$x=\frac{-2±\sqrt{-100}}{2}$$

-100 ning kvadrat ildizini chiqarish.

$$x=\frac{-2±10i}{2}$$

x=\frac{-2±10i}{2} tenglamasini yeching, bunda ± musbat. -2 ni 10i ga qo'shish.

$$x=\frac{-2+10i}{2}$$

-2+10i ni 2 ga bo'lish.

$$x=-1+5i$$

x=\frac{-2±10i}{2} tenglamasini yeching, bunda ± manfiy. -2 dan 10i ni ayirish.

$$x=\frac{-2-10i}{2}$$

-2-10i ni 2 ga bo'lish.

$$x=-1-5i$$

Tenglama yechildi.

$$x=-1+5i x=-1-5i$$

Kvadratni yakunlash bo'yicha qadamlar

Bu kabi kvadrat tenglamalarni kvadratni yakunlab yechish mumkin. Kvadratni yechish uchun tenglama avval ushbu shaklda bo'lishi shart: x^{2}+bx=c.

$$x^{2}+2x+26=0$$

Tenglamaning ikkala tarafidan 26 ni ayirish.

$$x^{2}+2x+26-26=-26$$

O‘zidan 26 ayirilsa 0 qoladi.

$$x^{2}+2x=-26$$

2 ni bo‘lish, x shartining koeffitsienti, 2 ga 1 olish uchun. Keyin, 1 ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.

$$x^{2}+2x+1^{2}=-26+1^{2}$$

1 kvadratini chiqarish.

$$x^{2}+2x+1=-26+1$$

-26 ni 1 ga qo'shish.

$$x^{2}+2x+1=-25$$

x^{2}+2x+1 omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.

$$\left(x+1\right)^{2}=-25$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$\sqrt{\left(x+1\right)^{2}}=\sqrt{-25}$$

Qisqartirish.

$$x+1=5i x+1=-5i$$

Tenglamaning ikkala tarafidan 1 ni ayirish.

$$x=-1+5i x=-1-5i$$