x^2+2=10 eching

$$x ^ { 2 } + 2 = 10$$

x uchun yechish

$$x=2\sqrt{2}\approx 2,828427125$$

$$x=-2\sqrt{2}\approx -2,828427125$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 2 ni ayirish.

$$x^{2}=10-2$$

8 olish uchun 10 dan 2 ni ayirish.

$$x^{2}=8$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=2\sqrt{2} x=-2\sqrt{2}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 10 ni ayirish.

$$x^{2}+2-10=0$$

-8 olish uchun 2 dan 10 ni ayirish.

$$x^{2}-8=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -8 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-8\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-8\right)}}{2}$$

-4 ni -8 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{32}}{2}$$

32 ning kvadrat ildizini chiqarish.

$$x=\frac{0±4\sqrt{2}}{2}$$

x=\frac{0±4\sqrt{2}}{2} tenglamasini yeching, bunda ± musbat.

$$x=2\sqrt{2}$$

x=\frac{0±4\sqrt{2}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-2\sqrt{2}$$

Tenglama yechildi.

$$x=2\sqrt{2} x=-2\sqrt{2}$$