x^2+17x+6 eching

$$x ^ { 2 } + 17 x + 6$$

Omil

$$\left(x-\frac{-\sqrt{265}-17}{2}\right)\left(x-\frac{\sqrt{265}-17}{2}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$x^{2}+17x+6=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-17±\sqrt{17^{2}-4\times 6}}{2}$$

17 kvadratini chiqarish.

$$x=\frac{-17±\sqrt{289-4\times 6}}{2}$$

-4 ni 6 marotabaga ko'paytirish.

$$x=\frac{-17±\sqrt{289-24}}{2}$$

289 ni -24 ga qo'shish.

$$x=\frac{-17±\sqrt{265}}{2}$$

x=\frac{-17±\sqrt{265}}{2} tenglamasini yeching, bunda ± musbat. -17 ni \sqrt{265} ga qo'shish.

$$x=\frac{\sqrt{265}-17}{2}$$

x=\frac{-17±\sqrt{265}}{2} tenglamasini yeching, bunda ± manfiy. -17 dan \sqrt{265} ni ayirish.

$$x=\frac{-\sqrt{265}-17}{2}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-17+\sqrt{265}}{2} ga va x_{2} uchun \frac{-17-\sqrt{265}}{2} ga bo‘ling.

$$x^{2}+17x+6=\left(x-\frac{\sqrt{265}-17}{2}\right)\left(x-\frac{-\sqrt{265}-17}{2}\right)$$

Baholash

$$x^{2}+17x+6$$