x^2+14x+22 eching

$$x ^ { 2 } + 14 x + 22$$

Omil

$$\left(x-\left(-3\sqrt{3}-7\right)\right)\left(x-\left(3\sqrt{3}-7\right)\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$x^{2}+14x+22=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-14±\sqrt{14^{2}-4\times 22}}{2}$$

14 kvadratini chiqarish.

$$x=\frac{-14±\sqrt{196-4\times 22}}{2}$$

-4 ni 22 marotabaga ko'paytirish.

$$x=\frac{-14±\sqrt{196-88}}{2}$$

196 ni -88 ga qo'shish.

$$x=\frac{-14±\sqrt{108}}{2}$$

108 ning kvadrat ildizini chiqarish.

$$x=\frac{-14±6\sqrt{3}}{2}$$

x=\frac{-14±6\sqrt{3}}{2} tenglamasini yeching, bunda ± musbat. -14 ni 6\sqrt{3} ga qo'shish.

$$x=\frac{6\sqrt{3}-14}{2}$$

-14+6\sqrt{3} ni 2 ga bo'lish.

$$x=3\sqrt{3}-7$$

x=\frac{-14±6\sqrt{3}}{2} tenglamasini yeching, bunda ± manfiy. -14 dan 6\sqrt{3} ni ayirish.

$$x=\frac{-6\sqrt{3}-14}{2}$$

-14-6\sqrt{3} ni 2 ga bo'lish.

$$x=-3\sqrt{3}-7$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun -7+3\sqrt{3} ga va x_{2} uchun -7-3\sqrt{3} ga bo‘ling.

$$x^{2}+14x+22=\left(x-\left(3\sqrt{3}-7\right)\right)\left(x-\left(-3\sqrt{3}-7\right)\right)$$

Baholash

$$x^{2}+14x+22$$