x^0=frac{30+4^2+sqrt{8}1+5^2x5}{4x+15+2(6-5)} eching

$$x ^ { 0 } = \frac { 30 + 4 ^ { 2 } + \sqrt { 8 } 1 + 5 ^ { 2 } x 5 } { 4 x + 15 + 2 ( 6 - 5 ) }$$

x_5 uchun yechish

$$x_{5}=\frac{4x-2\sqrt{2}-29}{25}$$

$$x\neq 0\text{ and }x\neq -\frac{17}{4}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini 4x+17 ga ko'paytirish.

$$\left(4x+17\right)x^{0}=30+4^{2}+1\sqrt{8}+5^{2}x_{5}$$

4x+17 ga x^{0} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$4xx^{0}+17x^{0}=30+4^{2}+1\sqrt{8}+5^{2}x_{5}$$

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. 1 va 0 ni qo‘shib, 1 ni oling.

$$4x^{1}+17x^{0}=30+4^{2}+1\sqrt{8}+5^{2}x_{5}$$

1 daraja ko‘rsatkichini x ga hisoblang va x ni qiymatni oling.

$$4x+17x^{0}=30+4^{2}+1\sqrt{8}+5^{2}x_{5}$$

2 daraja ko‘rsatkichini 4 ga hisoblang va 16 ni qiymatni oling.

$$4x+17x^{0}=30+16+1\sqrt{8}+5^{2}x_{5}$$

46 olish uchun 30 va 16'ni qo'shing.

$$4x+17x^{0}=46+1\sqrt{8}+5^{2}x_{5}$$

Faktor: 8=2^{2}\times 2. \sqrt{2^{2}\times 2} koʻpaytmasining kvadrat ildizini \sqrt{2^{2}}\sqrt{2} kvadrat ildizlarining koʻpaytmasi sifatida qayta yozing. 2^{2} ning kvadrat ildizini chiqarish.

$$4x+17x^{0}=46+1\times 2\sqrt{2}+5^{2}x_{5}$$

2 hosil qilish uchun 1 va 2 ni ko'paytirish.

$$4x+17x^{0}=46+2\sqrt{2}+5^{2}x_{5}$$

2 daraja ko‘rsatkichini 5 ga hisoblang va 25 ni qiymatni oling.

$$4x+17x^{0}=46+2\sqrt{2}+25x_{5}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$46+2\sqrt{2}+25x_{5}=4x+17x^{0}$$

Ikkala tarafdan 46 ni ayirish.

$$2\sqrt{2}+25x_{5}=4x+17x^{0}-46$$

Ikkala tarafdan 2\sqrt{2} ni ayirish.

$$25x_{5}=4x+17x^{0}-46-2\sqrt{2}$$

Tenglama standart shaklda.

$$25x_{5}=4x-2\sqrt{2}-29$$

Ikki tarafini 25 ga bo‘ling.

$$\frac{25x_{5}}{25}=\frac{4x-2\sqrt{2}-29}{25}$$

25 ga bo'lish 25 ga ko'paytirishni bekor qiladi.

$$x_{5}=\frac{4x-2\sqrt{2}-29}{25}$$

x uchun yechish (complex solution)

$$x=\frac{25x_{5}}{4}+\frac{\sqrt{2}}{2}+\frac{29}{4}$$

$$x_{5}\neq \frac{-2\sqrt{2}-29}{25}\text{ and }x_{5}\neq \frac{-2\sqrt{2}-46}{25}\text{ and }x_{5}\neq \frac{-2\sqrt{2}-29}{25}$$

x uchun yechish

$$x=\frac{25x_{5}}{4}+\frac{\sqrt{2}}{2}+\frac{29}{4}$$

$$x_{5}\neq \frac{-2\sqrt{2}-29}{25}\text{ and }x_{5}\neq \frac{-2\sqrt{2}-46}{25}$$