x^-3=(1/x)^3 eching

$$x ^ { - 3 } = ( \frac { 1 } { x } ) ^ { 3 }$$

x uchun yechish

$$x\neq 0$$

Qisqa yechim qadamlari

\frac{1}{x}ni darajaga oshirish uchun, surat va maxrajni darajaga oshirib, keyin bo‘ling.

$$x^{-3}=\frac{1^{3}}{x^{3}}$$

3 daraja ko‘rsatkichini 1 ga hisoblang va 1 ni qiymatni oling.

$$x^{-3}=\frac{1}{x^{3}}$$

Ikkala tarafdan \frac{1}{x^{3}} ni ayirish.

$$x^{-3}-\frac{1}{x^{3}}=0$$

Ifodalarni qo‘shish yoki ayirish uchun ularni yoyib, maxrajlarini bir xil qiling. x^{-3} ni \frac{x^{3}}{x^{3}} marotabaga ko'paytirish.

$$\frac{x^{-3}x^{3}}{x^{3}}-\frac{1}{x^{3}}=0$$

\frac{x^{-3}x^{3}}{x^{3}} va \frac{1}{x^{3}} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$\frac{x^{-3}x^{3}-1}{x^{3}}=0$$

x^{-3}x^{3}-1 ichidagi ko‘paytirishlarni bajaring.

$$\frac{1-1}{x^{3}}=0$$

1-1 hisob-kitobini qiling.

$$\frac{0}{x^{3}}=0$$

x qiymati 0 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini x^{3} ga ko'paytirish.

$$0=0$$

Bu har qanday x uchun to‘g‘ri.

$$x\in \mathrm{R}$$

x qiymati 0 teng bo‘lmaydi.

$$x\in \mathrm{R}\setminus 0$$