x=-3x^2 eching

$$x = - 3 x ^ { 2 }$$

x uchun yechish

$$x=-\frac{1}{3}\approx -0,333333333$$

$$x=0$$

Faktorlash qadamlari

3x^{2} ni ikki tarafga qo’shing.

$$x+3x^{2}=0$$

x omili.

$$x\left(1+3x\right)=0$$

Tenglamani yechish uchun x=0 va 1+3x=0 ni yeching.

$$x=0 x=-\frac{1}{3}$$

Kvadrat tenglamalaridan foydalanish qoidalari

3x^{2} ni ikki tarafga qo’shing.

$$x+3x^{2}=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$3x^{2}+x=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 3 ni a, 1 ni b va 0 ni c bilan almashtiring.

$$x=\frac{-1±\sqrt{1^{2}}}{2\times 3}$$

1^{2} ning kvadrat ildizini chiqarish.

$$x=\frac{-1±1}{2\times 3}$$

2 ni 3 marotabaga ko'paytirish.

$$x=\frac{-1±1}{6}$$

x=\frac{-1±1}{6} tenglamasini yeching, bunda ± musbat. -1 ni 1 ga qo'shish.

$$x=\frac{0}{6}$$

0 ni 6 ga bo'lish.

$$x=0$$

x=\frac{-1±1}{6} tenglamasini yeching, bunda ± manfiy. -1 dan 1 ni ayirish.

$$x=-\frac{2}{6}$$

\frac{-2}{6} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x=-\frac{1}{3}$$

Tenglama yechildi.

$$x=0 x=-\frac{1}{3}$$

Kvadratni yakunlash bo'yicha qadamlar

3x^{2} ni ikki tarafga qo’shing.

$$x+3x^{2}=0$$

Bu kabi kvadrat tenglamalarni kvadratni yakunlab yechish mumkin. Kvadratni yechish uchun tenglama avval ushbu shaklda bo'lishi shart: x^{2}+bx=c.

$$3x^{2}+x=0$$

Ikki tarafini 3 ga bo‘ling.

$$\frac{3x^{2}+x}{3}=\frac{0}{3}$$

3 ga bo'lish 3 ga ko'paytirishni bekor qiladi.

$$x^{2}+\frac{1}{3}x=\frac{0}{3}$$

0 ni 3 ga bo'lish.

$$x^{2}+\frac{1}{3}x=0$$

\frac{1}{3} ni bo‘lish, x shartining koeffitsienti, 2 ga \frac{1}{6} olish uchun. Keyin, \frac{1}{6} ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.

$$x^{2}+\frac{1}{3}x+\left(\frac{1}{6}\right)^{2}=\left(\frac{1}{6}\right)^{2}$$

Kasrning ham suratini, ham maxrajini kvadratga ko'paytirib \frac{1}{6} kvadratini chiqarish.

$$x^{2}+\frac{1}{3}x+\frac{1}{36}=\frac{1}{36}$$

x^{2}+\frac{1}{3}x+\frac{1}{36} omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.

$$\left(x+\frac{1}{6}\right)^{2}=\frac{1}{36}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$\sqrt{\left(x+\frac{1}{6}\right)^{2}}=\sqrt{\frac{1}{36}}$$

Qisqartirish.

$$x+\frac{1}{6}=\frac{1}{6} x+\frac{1}{6}=-\frac{1}{6}$$

Tenglamaning ikkala tarafidan \frac{1}{6} ni ayirish.

$$x=0 x=-\frac{1}{3}$$