x=-1/y-1+3/4 eching

$$x = - \frac { 1 } { y - 1 } + \frac { 3 } { 4 }$$

y uchun yechish

$$y=-\frac{7-4x}{4x-3}$$

$$x\neq \frac{3}{4}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

y qiymati 1 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini 4\left(y-1\right) ga, y-1,4 ning eng kichik karralisiga ko‘paytiring.

$$x\times 4\left(y-1\right)=-4+4\left(y-1\right)\times \frac{3}{4}$$

x\times 4 ga y-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$4xy-x\times 4=-4+4\left(y-1\right)\times \frac{3}{4}$$

-4 hosil qilish uchun -1 va 4 ni ko'paytirish.

$$4xy-4x=-4+4\left(y-1\right)\times \frac{3}{4}$$

3 hosil qilish uchun 4 va \frac{3}{4} ni ko'paytirish.

$$4xy-4x=-4+3\left(y-1\right)$$

3 ga y-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$4xy-4x=-4+3y-3$$

-7 olish uchun -4 dan 3 ni ayirish.

$$4xy-4x=-7+3y$$

Ikkala tarafdan 3y ni ayirish.

$$4xy-4x-3y=-7$$

4x ni ikki tarafga qo’shing.

$$4xy-3y=-7+4x$$

y'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(4x-3\right)y=-7+4x$$

Tenglama standart shaklda.

$$\left(4x-3\right)y=4x-7$$

Ikki tarafini 4x-3 ga bo‘ling.

$$\frac{\left(4x-3\right)y}{4x-3}=\frac{4x-7}{4x-3}$$

4x-3 ga bo'lish 4x-3 ga ko'paytirishni bekor qiladi.

$$y=\frac{4x-7}{4x-3}$$

y qiymati 1 teng bo‘lmaydi.

$$y=\frac{4x-7}{4x-3}\text{, }y\neq 1$$

x uchun yechish

$$x=-\frac{7-3y}{4\left(y-1\right)}$$

$$y\neq 1$$