y uchun yechish (complex solution)
\left\{\begin{matrix}\\y=\sqrt{x}\text{, }&\text{unconditionally}\\y\in \mathrm{C}\text{, }&x=0\end{matrix}\right,
y uchun yechish
\left\{\begin{matrix}y=\sqrt{x}\text{, }&x\geq 0\\y\in \mathrm{R}\text{, }&x=0\end{matrix}\right,
x uchun yechish (complex solution)
\left\{\begin{matrix}\\x=0\text{, }&\text{unconditionally}\\x=y^{2}\text{, }&arg(y)<\pi \text{ or }y=0\end{matrix}\right,
x uchun yechish
\left\{\begin{matrix}\\x=0\text{, }&\text{unconditionally}\\x=y^{2}\text{, }&y\geq 0\end{matrix}\right,
Grafik
Baham ko'rish
Klipbordga nusxa olish
y\sqrt{x}=x
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
\sqrt{x}y=x
Tenglama standart shaklda.
\frac{\sqrt{x}y}{\sqrt{x}}=\frac{x}{\sqrt{x}}
Ikki tarafini \sqrt{x} ga bo‘ling.
y=\frac{x}{\sqrt{x}}
\sqrt{x} ga bo'lish \sqrt{x} ga ko'paytirishni bekor qiladi.
y=\sqrt{x}
x ni \sqrt{x} ga bo'lish.
y\sqrt{x}=x
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
\sqrt{x}y=x
Tenglama standart shaklda.
\frac{\sqrt{x}y}{\sqrt{x}}=\frac{x}{\sqrt{x}}
Ikki tarafini \sqrt{x} ga bo‘ling.
y=\frac{x}{\sqrt{x}}
\sqrt{x} ga bo'lish \sqrt{x} ga ko'paytirishni bekor qiladi.
y=\sqrt{x}
x ni \sqrt{x} ga bo'lish.
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