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x^{2}+x=3
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
x^{2}+x-3=3-3
Tenglamaning ikkala tarafidan 3 ni ayirish.
x^{2}+x-3=0
O‘zidan 3 ayirilsa 0 qoladi.
x=\frac{-1±\sqrt{1^{2}-4\left(-3\right)}}{2}
Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 1 ni b va -3 ni c bilan almashtiring.
x=\frac{-1±\sqrt{1-4\left(-3\right)}}{2}
1 kvadratini chiqarish.
x=\frac{-1±\sqrt{1+12}}{2}
-4 ni -3 marotabaga ko'paytirish.
x=\frac{-1±\sqrt{13}}{2}
1 ni 12 ga qo'shish.
x=\frac{\sqrt{13}-1}{2}
x=\frac{-1±\sqrt{13}}{2} tenglamasini yeching, bunda ± musbat. -1 ni \sqrt{13} ga qo'shish.
x=\frac{-\sqrt{13}-1}{2}
x=\frac{-1±\sqrt{13}}{2} tenglamasini yeching, bunda ± manfiy. -1 dan \sqrt{13} ni ayirish.
x=\frac{\sqrt{13}-1}{2} x=\frac{-\sqrt{13}-1}{2}
Tenglama yechildi.
x^{2}+x=3
Bu kabi kvadrat tenglamalarni kvadratni yakunlab yechish mumkin. Kvadratni yechish uchun tenglama avval ushbu shaklda bo'lishi shart: x^{2}+bx=c.
x^{2}+x+\left(\frac{1}{2}\right)^{2}=3+\left(\frac{1}{2}\right)^{2}
1 ni bo‘lish, x shartining koeffitsienti, 2 ga \frac{1}{2} olish uchun. Keyin, \frac{1}{2} ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.
x^{2}+x+\frac{1}{4}=3+\frac{1}{4}
Kasrning ham suratini, ham maxrajini kvadratga ko'paytirib \frac{1}{2} kvadratini chiqarish.
x^{2}+x+\frac{1}{4}=\frac{13}{4}
3 ni \frac{1}{4} ga qo'shish.
\left(x+\frac{1}{2}\right)^{2}=\frac{13}{4}
x^{2}+x+\frac{1}{4} omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.
\sqrt{\left(x+\frac{1}{2}\right)^{2}}=\sqrt{\frac{13}{4}}
Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.
x+\frac{1}{2}=\frac{\sqrt{13}}{2} x+\frac{1}{2}=-\frac{\sqrt{13}}{2}
Qisqartirish.
x=\frac{\sqrt{13}-1}{2} x=\frac{-\sqrt{13}-1}{2}
Tenglamaning ikkala tarafidan \frac{1}{2} ni ayirish.