A uchun yechish (complex solution)
\left\{\begin{matrix}A=-\frac{-x^{3}+2x-u}{3xy}\text{, }&y\neq 0\text{ and }x\neq 0\\A\in \mathrm{C}\text{, }&\left(u=0\text{ and }x=0\right)\text{ or }\left(u=x\left(2-x^{2}\right)\text{ and }y=0\right)\end{matrix}\right,
A uchun yechish
\left\{\begin{matrix}A=-\frac{-x^{3}+2x-u}{3xy}\text{, }&y\neq 0\text{ and }x\neq 0\\A\in \mathrm{R}\text{, }&\left(u=0\text{ and }x=0\right)\text{ or }\left(u=x\left(2-x^{2}\right)\text{ and }y=0\right)\end{matrix}\right,
u uchun yechish
u=-x\left(x^{2}-3Ay-2\right)
Grafik
Baham ko'rish
Klipbordga nusxa olish
2x-x^{3}+3xyA=u
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
-x^{3}+3xyA=u-2x
Ikkala tarafdan 2x ni ayirish.
3xyA=u-2x+x^{3}
x^{3} ni ikki tarafga qo’shing.
3xyA=x^{3}-2x+u
Tenglama standart shaklda.
\frac{3xyA}{3xy}=\frac{x^{3}-2x+u}{3xy}
Ikki tarafini 3xy ga bo‘ling.
A=\frac{x^{3}-2x+u}{3xy}
3xy ga bo'lish 3xy ga ko'paytirishni bekor qiladi.
2x-x^{3}+3xyA=u
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
-x^{3}+3xyA=u-2x
Ikkala tarafdan 2x ni ayirish.
3xyA=u-2x+x^{3}
x^{3} ni ikki tarafga qo’shing.
3xyA=x^{3}-2x+u
Tenglama standart shaklda.
\frac{3xyA}{3xy}=\frac{x^{3}-2x+u}{3xy}
Ikki tarafini 3xy ga bo‘ling.
A=\frac{x^{3}-2x+u}{3xy}
3xy ga bo'lish 3xy ga ko'paytirishni bekor qiladi.
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