t=290-300/50/sqrt{15} eching

$$t = \frac { 290 - 300 } { 50 / \sqrt { 15 } }$$

t uchun yechish

$$t=-\frac{\sqrt{15}}{5}\approx -0,774596669$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-10 olish uchun 290 dan 300 ni ayirish.

$$t=\frac{-10}{\frac{50}{\sqrt{15}}}$$

\frac{50}{\sqrt{15}} maxrajini \sqrt{15} orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.

$$t=\frac{-10}{\frac{50\sqrt{15}}{\left(\sqrt{15}\right)^{2}}}$$

\sqrt{15} kvadrati – 15.

$$t=\frac{-10}{\frac{50\sqrt{15}}{15}}$$

\frac{10}{3}\sqrt{15} ni olish uchun 50\sqrt{15} ni 15 ga bo‘ling.

$$t=\frac{-10}{\frac{10}{3}\sqrt{15}}$$

\frac{-10}{\frac{10}{3}\sqrt{15}} maxrajini \sqrt{15} orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.

$$t=\frac{-10\sqrt{15}}{\frac{10}{3}\left(\sqrt{15}\right)^{2}}$$

\sqrt{15} kvadrati – 15.

$$t=\frac{-10\sqrt{15}}{\frac{10}{3}\times 15}$$

Surat va maxrajdagi ikkala 5 ni qisqartiring.

$$t=\frac{-2\sqrt{15}}{3\times \frac{10}{3}}$$

3 va 3 ni qisqartiring.

$$t=\frac{-2\sqrt{15}}{10}$$

-\frac{1}{5}\sqrt{15} ni olish uchun -2\sqrt{15} ni 10 ga bo‘ling.

$$t=-\frac{1}{5}\sqrt{15}$$

t'ni tayinlash

$$t≔-\frac{\sqrt{15}}{5}$$