s=1/2gt^2+v_{0}t.quadd eching

$$s = \frac { 1 } { 2 } g t ^ { 2 } + v _ { 0 } t . \quad d$$

g uchun yechish

$$\left\{\begin{matrix}g=-\frac{2\left(tv_{0}-s\right)}{t^{2}}\text{, }&t\neq 0\\g\in \mathrm{R}\text{, }&s=0\text{ and }t=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\frac{1}{2}gt^{2}+v_{0}t=s$$

Ikkala tarafdan v_{0}t ni ayirish.

$$\frac{1}{2}gt^{2}=s-v_{0}t$$

Tenglama standart shaklda.

$$\frac{t^{2}}{2}g=s-tv_{0}$$

Ikki tarafini \frac{1}{2}t^{2} ga bo‘ling.

$$\frac{2\times \frac{t^{2}}{2}g}{t^{2}}=\frac{2\left(s-tv_{0}\right)}{t^{2}}$$

\frac{1}{2}t^{2} ga bo'lish \frac{1}{2}t^{2} ga ko'paytirishni bekor qiladi.

$$g=\frac{2\left(s-tv_{0}\right)}{t^{2}}$$

s uchun yechish

$$s=\frac{t\left(gt+2v_{0}\right)}{2}$$