r=a*sec2θ eching

$$r = a \cdot \sec 2 \theta$$

a uchun yechish

$$a=r\cos(2\theta )$$

$$\nexists n_{1}\in \mathrm{Z}\text{ : }\theta =\frac{\pi n_{1}}{2}+\frac{\pi }{4}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$a\sec(2\theta )=r$$

Tenglama standart shaklda.

$$\sec(2\theta )a=r$$

Ikki tarafini \sec(2\theta ) ga bo‘ling.

$$\frac{\sec(2\theta )a}{\sec(2\theta )}=\frac{r}{\sec(2\theta )}$$

\sec(2\theta ) ga bo'lish \sec(2\theta ) ga ko'paytirishni bekor qiladi.

$$a=\frac{r}{\sec(2\theta )}$$

r ni \sec(2\theta ) ga bo'lish.

$$a=r\cos(2\theta )$$

r uchun yechish

$$r=\frac{a}{\cos(2\theta )}$$

$$\nexists n_{1}\in \mathrm{Z}\text{ : }\theta =\frac{\pi n_{1}}{2}+\frac{\pi }{4}$$