px^2-q=r eching

$$p x ^ { 2 } - q = r$$

p uchun yechish

$$\left\{\begin{matrix}p=\frac{q+r}{x^{2}}\text{, }&x\neq 0\\p\in \mathrm{R}\text{, }&q=-r\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

q ni ikki tarafga qo’shing.

$$px^{2}=r+q$$

Tenglama standart shaklda.

$$x^{2}p=q+r$$

Ikki tarafini x^{2} ga bo‘ling.

$$\frac{x^{2}p}{x^{2}}=\frac{q+r}{x^{2}}$$

x^{2} ga bo'lish x^{2} ga ko'paytirishni bekor qiladi.

$$p=\frac{q+r}{x^{2}}$$

q uchun yechish

$$q=px^{2}-r$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan px^{2} ni ayirish.

$$-q=r-px^{2}$$

Ikki tarafini -1 ga bo‘ling.

$$\frac{-q}{-1}=\frac{r-px^{2}}{-1}$$

-1 ga bo'lish -1 ga ko'paytirishni bekor qiladi.

$$q=\frac{r-px^{2}}{-1}$$

-px^{2}+r ni -1 ga bo'lish.

$$q=px^{2}-r$$