p^2*3p^2*3p^3= eching

$$p ^ { 2 } \times 3 p ^ { 2 } \times 3 p ^ { 3 } =$$

Baholash

$$9p^{7}$$

Yechim qadamlari

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. 2 va 2 ni qo‘shib, 4 ni oling.

$$p^{4}\times 3\times 3p^{3}$$

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. 4 va 3 ni qo‘shib, 7 ni oling.

$$p^{7}\times 3\times 3$$

9 hosil qilish uchun 3 va 3 ni ko'paytirish.

$$p^{7}\times 9$$

p ga nisbatan hosilani topish

$$63p^{6}$$

Derivativ ifodasidan foydalanish qadamlari

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. 2 va 2 ni qo‘shib, 4 ni oling.

$$\frac{\mathrm{d}}{\mathrm{d}p}(p^{4}\times 3\times 3p^{3})$$

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. 4 va 3 ni qo‘shib, 7 ni oling.

$$\frac{\mathrm{d}}{\mathrm{d}p}(p^{7}\times 3\times 3)$$

9 hosil qilish uchun 3 va 3 ni ko'paytirish.

$$\frac{\mathrm{d}}{\mathrm{d}p}(p^{7}\times 9)$$

ax^{n} hosilasi – nax^{n-1}.

$$7\times 9p^{7-1}$$

7 ni 9 marotabaga ko'paytirish.

$$63p^{7-1}$$

7 dan 1 ni ayirish.

$$63p^{6}$$